25m^2+25m+6=0

Solution for 25m^2+25m+6=0 equation:

25m^2+25m+6=0

a = 25; b = 25; c = +6;
Δ = b2-4ac
Δ = 252-4·25·6
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5}{2*25}=\frac{-30}{50}
=-3/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5}{2*25}=\frac{-20}{50}
=-2/5
$